99a^2+55a=0

Solution for 99a^2+55a=0 equation:

99a^2+55a=0

a = 99; b = 55; c = 0;
Δ = b2-4ac
Δ = 552-4·99·0
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-55}{2*99}=\frac{-110}{198}
=-5/9
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+55}{2*99}=\frac{0}{198}
=0
$